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5_6_2_Spannungsglaettung_mit_Kondensator

FE

feslehrer

·

Created Nov 10, 2026

·

Updated Nov 10, 2026

Schematic preview for 5_6_2_Spannungsglaettung_mit_Kondensator
Details

Components

5


Schematic

Yes


Simulation

Transient analysis


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About this circuit

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Circuit notes

Einweggleichrichter


Arbeitsauftrag

  1. Starten Sie die Simulation.
    Welche Beobachtung machen Sie zu Ud und UF?
  2. Messen Sie mit dem Cursor die Spannungen Û1, Ûd und UF
    Welchen Zusammenhang zwischen diesen 3 Spannungen können Sie erkennen?

Die ideelle Leerlaufspannung Udi entspricht dem arithmetischen Mittelwert der Gleichspannung für eine ideale Diode (UF = 0 V). Man nennt sie auch Gleichrichtwert.

Kennzeichnung

E1U = Einwegschaltung, Pulszahl 1, Ungesteuert

Components used

Components used
5 components
NameManufacturerMPNCountType

Diode

Generic

—

1

Official

Polarized Capacitor

Generic

—

1

Official

Resistor

Generic

—

1

Official

RMS AC Voltage Source

Generic

—

1

Official

SPICE netlist

* **************************************************
* Generated from CircuitSim Schematic
**************************************************
* net label L1 joins NET_005::component:node-7216812e-2923-46f4-a103-897d7f879240:T0 NET_005::node:junction-e5a710e4-2bfe-4eef-be00-f4417aa21645
* net label N joins NET_006::node:junction-0376c36a-d530-4e5d-b886-284d946fefeb NET_006::node:junction-e6f9e1ee-0694-4c09-9a7f-7360576e1783
X_C1 N7 0 POLARIZED_CAPACITOR C=200u RLEAK=10meg ISREV=1e-12 NREV=1.8 RSREV=0.2
X_R1 N4 N6 DIODE_25d079d4 IS=1e-14 RS=0 N=1 BV=1e30 IBV=100p CJO=0 VJ=1 M=0.5 TT=0 EG=1.11 XTI=3 KF=0 AF=1 FC=0.5 ISR=0 NR=2 IKF=1e30 TNOM=27 IC=0 TEMP=27
R_RL N5 0 100 Resistor_1d9c8cf9a__R_RL
X_T1 N3 0 N4 0 Param1P1S_e1d792b5 PTurns=2.147K PNegativePolarity=0 STurns=112 SNegativePolarity=0
V_Unetz N3 0 dc 0 ac 1 0 distof1 0 0 distof2 0 0 sin ( 0 {230*1.414213562} 50 0 0 0 )
E_VP1 VP1 0 N3 0 1
E_VP2 VP2 0 N4 0 1
E_VP4 VP4 0 N5 0 1
V_IP2 N7 N5 0
V_IP1 N6 N7 0

**************************************************
* Models and supporting definitions follow
**************************************************
.SUBCKT POLARIZED_CAPACITOR P N PARAMS: C=10u RLEAK=10Meg ISREV=1e-12 NREV=1.8 RSREV=0.2
    C1 P N {C}
    RLEAK P N {RLEAK}
    .model PCAPREV D(IS={ISREV} N={NREV} RS={RSREV})
    DREV N P PCAPREV
.ENDS POLARIZED_CAPACITOR
* Source-compatible two-terminal junction diode
.subckt DIODE_25d079d4 A K params: IS=1e-14 RS=0 N=1 BV=1e30 IBV=100p CJO=0 VJ=1 M=0.5 TT=0 EG=1.11 XTI=3 KF=0 AF=1 FC=0.5 ISR=0 NR=2 IKF=1e30 TNOM=27 IC=0 TEMP=27
    .model DIODE_25d079d4_CORE D(IS={IS} RS={RS} N={N} BV={BV} IBV={IBV} CJO={CJO} VJ={VJ} M={M} TT={TT} EG={EG} XTI={XTI} KF={KF} AF={AF} FC={FC} ISR={ISR} NR={NR} IKF={IKF} TNOM={TNOM})
    DCORE A K DIODE_25d079d4_CORE IC={IC} TEMP={TEMP}
.ends DIODE_25d079d4
.model Resistor_1d9c8cf9a__R_RL r(tc1=0 tc2=0 tnom=27)
.subckt Param1P1S_e1d792b5 p1pos p1neg s1pos s1neg params: PTurns=10 PNegativePolarity=0 STurns=1 SNegativePolarity=0
    .param PTurnsEffective = {PTurns * ((PNegativePolarity < 0.5) ? 1 : -1)}

    .param STurnsEffective = {STurns * ((SNegativePolarity < 0.5) ? 1 : -1)}

    G1 p1pos p1neg value={-1/PTurnsEffective*(STurnsEffective*I(Es1))}
    Es1 s1pos s1neg value={V(p1pos,p1neg)*STurnsEffective/PTurnsEffective}
.ENDS

**************************************************
* Simulation settings
**************************************************
.tran 2u 0.08 0 2u
.save V(VP2) V(VP4) V(VP1) I(V_IP1) I(V_IP2)
.end

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